subway202313
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WILL GIVE BRAINLIEST!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Y = x² + 6x + 3
What is the vertex?
What is the y-intercept?
Does the parabola open up or down?

Respuesta :

bunnyo

Answer:

x^2+6x+3=0

(X+3)^2-9+3=0

since (x+3)^2>=0 for any real value of x

at vertex

(X+3)^2=0

X=-3

i.e y=0-9+3=-6

vertex (-3,-6)

at y intercept x=0

y=3

x^2 coefficient is positive

therefore this is a concave up graph

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