contestada

In 2015 the populations of City X and City Y were
equal. From 2010 to 2015, the population of City X
increased by 20% and the population of City Y
decreased by 10%. If the population of City X was
120,000 in 2010, what was the population of City Y
in 2010?

Respuesta :

ak909

Answer:

160,000

Step-by-step explanation:

120,000 + 0.2(120,000)=120,000+24,000=144,000

144,000 were both populations in 2015.

x-0.1x = 144,000

0.9x=144,000

x=160,000

The Population of City Y in 2010 was 160,000

The population of City Y in 2010 is 160,000.

Given that,

  • In the year 2015, the populations of City X and City Y were  equal.
  • City X population is increased by 20% and City Y population is decreased by 10% from 2010 to 2015.
  • Also, the population of City X was  120,000 in 2010.

Based on the above information, the calculation is as follows:

= 120,000 + 0.2(120,000)

= 120,000+24,000

= 144,000

Now  

x - 0.1x = 144,000

0.9x = 144,000

x = 160,000

Therefore we can conclude that the population of City Y in 2010 is 160,000.

Learn more: brainly.com/question/8696744

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