Answer:
The strength of the magnetic field is 3.73 T.
Explanation:
We have,
Current in the wire is 3 A
Length of wire, L = 4.2 cm = 0.042 m
A wire crosses perpendicularly between the two poles of a strong horseshoe magnet.
When the current is turned on, the wire experiences 0.47 N of force, F = 0.47 N
It is required to find the strength of the magnetic field. The magnetic force acting on the wire is given by :
[tex]F=iLB\sin\theta[/tex]
B is strength of the magnetic field
[tex]B=\dfrac{F}{iL}\\\\B=\dfrac{0.47}{3\times 0.042}\\\\B=3.73\ T[/tex]
So, the strength of the magnetic field is 3.73 T.
