Respuesta :
Answer:
No.
Explanation:
- According to Faraday's law, the induced emf in the circuit is given by :
[tex]e=\dfrac{d\phi}{dt}[/tex], it is proportional to the rate of change of magnetic flux.
- In this case, a short piece of wire that is not attached to anything and move it up and down in a magnetic field. It means that the circuit is not completed here. It is an open circuit. For the induction of current, a circuit must be completed.
- Hence, no current will induce.
Answer:
Suppose you take a short piece of wire that is not attached to anything and move it up and down in a magnetic field. Explain whether or not a current will be induced, and why.According to Faraday's law, the induced emf in the circuit is given by : , it is proportional to the rate of change of magnetic flux. In this case, a short piece of wire that is not attached to anything and move it up and down in a magnetic field. It means that the circuit is not completed here. It is an open circuit. For the induction of current, a circuit must be completed. Hence, no current will induce. To make an electromagnet stronger, more coils can be added to the solenoid, a greater amount of current can be sent through the solenoid, and a larger or more magnetic piece of metal could be used in the core.
Explanation:
Thanks to the dude above me more part of this answer. If you want to learn DONT USE MY ANSWER I just basically copy and pasted abunch of text so that way the answer machine had enough key words to mark it as correct.
