xcrisba
contestada

WILL MARK BRAINIEST

Explain the steps necessary to convert a quadratic function in standard form to vertex form.

Respuesta :

Answer:

A quadratic function in standard form is converted to vertex form by completing the square. The first two terms are used to create a perfect square trinomial after a zero pair is added. The zero pair is found by taking half of the x-term coefficient and squaring it. The original constant term and the negative value of the zero pair are then combined.

Step-by-step explanation:

The vertex form of a quadratic equation is [tex]y=a(x-h)^2+k[/tex] and the vertex is (h, k) converted from the standard form [tex]y=ax^2+bx+c[/tex].

What is the standard form of a quadratic function?

The standard form of a quadratic function is [tex]y=ax^2+bx+c[/tex].

The equation whose variable's highest degree is 2 is said to be a quadratic equation.

Steps to convert standard form to vertex form:

The standard form is

[tex]y=ax^2+bx+c[/tex]

Step 1: taking a common from the terms

⇒ [tex]y=a(x^2+\frac{b}{a} x)+c[/tex]

Step 2: Factorization

[tex]y=a(x^2+\frac{b}{a} x+(\frac{b}{2a})^{2} -(\frac{b}{2a})^{2}) +c[/tex]

[tex]y=a(x+\frac{b}{2a} )^2+c-\frac{b^2}{4a}[/tex]

Step 3: Writing in the vertex form

[tex]y=a(x-(-\frac{b}{2a}) )^2+c-\frac{b^2}{4a}[/tex]

Where h = [tex]-\frac{b}{2a}[/tex] and k = [tex]c-\frac{b^2}{4a}[/tex]

So, the quadratic function's vertex form is [tex]y=a(x-(-\frac{b}{2a}) )^2+c-\frac{b^2}{4a}[/tex].

Learn more about the vertex form of  quadratic functions here:

https://brainly.com/question/15673828

#SPJ2