A dental laboratory technician earns $14 per hour when she work days and $18 per hour when she works nights. One month she works six 4 hour days, three 8-hours days, three 10-hour days, five 6-hour nights, and four 8-hour nights. What is her total pay for the month?

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Answer:

Her total pay for the month is $2208

Step-by-step explanation:

A dental laboratory technician earns $14 per hour when she work days and $18 per hour when she works nights.

One month :

She works six 4 hour days

So,total hours = [tex]6 \times 4 = 24 hours[/tex]

Three 8-hours days = [tex]3 \times 8 = 24 hours[/tex]

Three 10-hour days = [tex]3 \times 10 = 30 hours[/tex]

So, Total day hours = 24+24+30=78 hours

Cost of 1 hour day = $14

Cost of 78 hours day = [tex]14 \times 78 =1092[/tex]

Five 6-hour nights= [tex]5 \times 6 = 30 hours[/tex]

Four 8-hour nights =[tex]4 \times 8 = 32 hours[/tex]

Total night hours = 30+32=62 hours

Cost of 1 night hour = $18

Cost of 62 night hour = [tex]62 \times 18=1116[/tex]

So, Total pay for month = $1092+$1116 =2208

Hence her total pay for the month is $2208

Her total pay for the month is $2208

Given:

A dental laboratory technician earns $14 per hour when she work days and $18 per hour when she works nights.

One month:

Six 4 hour days = 6 x 4 = 24 hours

Three 8-hours days = 3 x 8 = 24 hours

Three 10-hour days = 3 x 10 = 30 hours

Five 6-hour nights = 5 x 6 = 30 hours

Four 8-hour nights = 4 x 8 = 32 hours

So, total hours work on day = 24 + 24 + 30 = 78 hours

Total hours work on night = 30 + 32 = 62 hours

Total pay for the month = 78(14) +  62(18) = $2208

Therefore, Total pay for the month is $2208

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