Answer:
Explanation:
Distance of each of the charges from the center are equal . If this distance be d
d = .5 x length of diagonal of square
length of diagonal = 4√2
d = .5 x 4√2
= 2√2
potential at a point
V = k Q / r where k is a constant , Q is charge and r is distance of the point from the charge .
k = 9 x 10⁹
Total potential = [tex]\frac{9\times10^9\times3 \times2}{2\sqrt{2} } -[/tex][tex]\frac{9\times10^9 \times2}{2\sqrt{2} }[/tex]
= [tex]\frac{9\times10^9 \times2\times2}{2\sqrt{2} }[/tex]
= 9 √2 x 10⁹ V .
