Answer:
Final temperature of the solution is 23.3°C
Explanation:
Mass of aluminium(M1) = 5g
Initial temperature of aluminium(T1) = 100°C
Mass of water (M2) = 25°C
Initial temperature of water(T2) = 20°C
Final temperature of the solution (T3) = ?
Specific heat capacity of aluminium = 0.9J/g°C
Specific heat capacity of water = 4.184J/g°C
Heat loss by Aluminium = Heat gained by water
Q = MC∇T
Q = heat energy
M = Mass
C = specific heat capacity
∇T = change in temperature
M1C1(T1 - T3) = M2C2(T3 - T2)
5 * 0.9 *(100 - T3) = 25 * 4.184 (T3 - 20)
4.5 * (100 - T3) = 104.6 (T3 - 20)
450 - 4.5T3 = 104.6T3 - 2092
Collect liketerms
450 + 2092 = 104.6T3 + 4.5T3
2542 = 109.1T3
T3 = 2542 / 109.1
T3 = 23.299°C = 23.3°C
Final temperature of the mixture is 23.3°C
