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4) When carbon disulfide burns in the presence of oxygen, sulfur dioxide and carbon
dioxide are produced according to the following equation:
CS2 + 3 O2 → CO2 + 2 SO2

a) What is the percent yield of sulfur dioxide if the burning of 25.0 g of carbon
disulfide produces 40.5 g of sulfur dioxide?

Respuesta :

Answer:

94.6% yield

Explanation:

[tex]25.0 g CS2 (\frac{1 mol CS2}{76 g CS2}) (\frac{2 mol SO2}{1 mol CS2} ) (\frac{64 g SO2}{1 mol SO2} ) = 42.8 g SO2[/tex]

42.8 g SO2  -> 100% yield

40.5 g SO2  -> x

x= (40.5 g SO2 * 100)/42.8 g SO2     x=94.6%

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