Respuesta :
Answer:
8.3%
Step-by-step explanation:
The sample space of a number cube with sides numbered 1 through 6 is rolled and a fair coin flipped is given below.
[tex]\left|\begin{array}{c|cccccc}--&--&---&--&--&--&--\\&1&2&3&4&5&6\\--&--&---&--&--&--&--\\H&H1&H2&H3&H4&H5&H6\\T&T1&T2&T3&T4&T5&T6\\--&--&---&--&--&--&--\end{array}\right|[/tex]
Number of Possible Outcomes=12
Therefore:
Probability of flipping a head AND rolling a 3
[tex]=\dfrac{1}{12} \\$Expressed as a percentage=\dfrac{1}{12}X100=8.3\%[/tex]
Using it's concept, it is found that there is a 8.3% probability of flipping a head AND rolling a 3.
What is a probability?
A probability is given by the number of desired outcomes divided by the number of total outcomes.
In this problem:
- A three is one of the six possible outcomes out of the cube, hence P(A) = 1/6.
- For the coin, the outcomes are equally as likely, hence the probability of tossing a heads is P(B) = 1/2.
Since the events are independent, the probability of flipping a head AND rolling a 3 is the multiplication of each probability, that is:
[tex]P(A \cap B) = P(A)P(B) = \frac{1}{6} \times \frac{1}{2} = 0.083 = 8.3\%[/tex]
8.3% probability of flipping a head AND rolling a 3.
More can be learned about probabilities at https://brainly.com/question/14398287
