Answer:
Answer is option d
Step-by-step explanation:
[tex]given \: equations \: are \\ 3x + 4y = - 2 \\ 2x - 4y = - 8 \\ on \: adding \: the \: above \: two \: equations \\ we \: get \: \: 5x = - 10 \\ x = \frac{ - 10}{5} \\ x = - 2 \\ substitute \: \: x = - 2 \: \: in \: first \: equation \: \\ 3( - 2) + 4y = - 2 \\ - 6 + 4y = - 2 \\ 4y = 6 - 2 \\ 4y = 4 \\ y = 1[/tex]
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