Answer:
Of the 16 possible experimental outcomes, 4 outcomes result in exactly 1 success.
The probability of a determined sample point with an outcome of one success is P=0.0992.
Step-by-step explanation:
We have a proportion of success (the selection of a manager who reads e-mail in the bathroom) of p=0.18.
The sample size is n=4.
We can model this as a binomial random variable.
The sample space is [0, 1, 2, 3, 4].
The possible outcomes for x=0 (that is no manager in the sample reads email in the bathroom) can be calculated as:
[tex]C(0)=\dbinom{4}{0}=\dfrac{4!}{4!0!}=1[/tex]
The same way we can calculate all the other possible outcomes:
[tex]C(1)=\dbinom{4}{1}=\dfrac{4!}{3!1!}=\dfrac{4}{1}=4\\\\\\C(2)=\dbinom{4}{2}=\dfrac{4!}{2!2!}=\dfrac{4*3}{2*2}=6\\\\\\C(3)=\dbinom{4}{3}=\dfrac{4!}{3!1!}=4\\\\\\C(4)=\dbinom{4}{4}=\dfrac{4!}{4!0!}=1[/tex]
The sum of this outcomes is 16 possible outcomes. Of the 16 possible experimental outcomes, 4 outcomes result in exactly 1 success.
The probability of an outcome with 1 success is the product of p (the one that reads email) times (1-p)^3 (the other 3 that do not read emails in the bathroom):
[tex]p\cdot (1-p)^3=0.18\cdot0.82^3=0.18\cdot 0.5514=0.0992[/tex]