Bats are mainly active at night. They have several senses that they use to find their way about, locate prey, avoid obstacles, and "see" in the dark. Besides the usual sense of vision, bats are able to emit high-frequency sound waves and hear the echo that bounces back when these sound waves hit an object. This sonar-like system is called echolocation. Typical frequencies emitted by bats are between 20 and 200 kHz. Note that the human ear is sensitive only to frequencies as high as 20 kHz.
a. Find the wavelength of the 80.0- KHz wave emitted by the bat.
b. Will the bat be able to locate the moth despite the darkness of the night?

Respuesta :

Answer:

a) 4.28 mm

b) Yes

Explanation:

a) To find the wavelength of the wave emitted by the bat you use the following formula:

[tex]v=\lambda f\\\\\lambda=\frac{v}{f}[/tex]

v: speed of sound = 343 m/s

f: frequency of the wave = 80*10^3 Hz

[tex]\lambda=\frac{343\ m/s}{80*10^3\ Hz}=4.28*10^{-3}m[/tex]

b) The bat is able to locate the moth because echolocation does not depend of light waves. Echolocation depends only of sound and night does not chage the basic properties of sound.

a) The wavelength of the 80.0- KHz wave emitted by the bat is [tex]4.28*10^{-3}m[/tex]

b) Yes, the bat be able to locate the moth despite the darkness of the night.

Relation between frequency and wavelength:

[tex]v=\lambda*f[/tex]

where,

Speed of sound,[tex]v = 343 m/s[/tex]

Frequency of the wave, [tex]f = 80*10^3 Hz[/tex]

Wavelength of the wave, [tex]\lambda\\[/tex]= ?

a) On substituting the values in the above formula:

[tex]v=\lambda*f\\\\\lambda=\frac{v}{f} \\\\\lambda=\frac{343 m/s}{80*1063 Hz}\\\\ \lambda=4.28*10^{-3}m[/tex]

Therefore, the wavelength of the 80.0- KHz wave emitted by the bat is [tex]4.28*10^{-3}m[/tex]

b) The bat is able to locate the moth because echolocation does not depend of light waves. Echolocation depends only of sound and night does not change the basic properties of sound.

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