The measure of angle QPR D.68°
According to the figure, the minor arc is 112°, so the other part of the circle would be 360° - 112° = 248°,
because a circle has 360° as total arc.
Now, when an external angle is formed by two tangents, that angle is defined as the half-difference between the intercepted arcs, which can be expressed as
[tex]$\angle Q P R=\frac{1}{2}(248-112)=\frac{1}{2}(136)$ $\angle Q P R=68^{\circ}$[/tex]
Therefore, the right answer is D.
An angle is outside a circle if its vertex is outside the circle and its sides are tangents or secants. The possibilities are: an angle formed by two tangents, an angle formed by a tangent and a secant, and an angle formed by two secants.
The measure of an angle formed by two secants, two tangents, or a secant and a tangent from a point outside the circle is half the difference of the measures of the intercepted arcs.
Learn more about Outside Angle Theorem, refer
https://brainly.com/question/12230244
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