What is the area? Please explain steps so I can attempt to understand

Answer:
[tex]12 \sqrt{2} [/tex]
Step-by-step explanation:
you can use hypotenuse formula
45-45-90 isosceles right triangle
so, 45= x
x² + x² = 24²
2x² = 24²
x²= 24.12
x= [tex] \sqrt{288} = 12 \sqrt{2} [/tex]
or :
you can use this rule: if you see a 45 45 90 isosceles right triagngle (you can look picture) 45=a cm and 90 = [tex] a\sqrt{2} [/tex]
cm
so ;
[tex]a \sqrt{2} = 24[/tex]
a= [tex]12 \sqrt{2} [/tex]
hope this helps ^-^