The quantity of charge q (in coulombs) that has passed through a surface of area 2.00 cm2 varies with time
according to the equation q(t) = 4t³ + 5t + 6, where t is in seconds. **(a) what is the electrical charge at (t = 2).
**(b) What is the instantaneous current through the surface at
t = 1.00 s?
**(c) What is the value of the current density? ​

Respuesta :

Explanation:

We have,

Surface area, [tex]A=2\ cm^2=0.0002\ m^2[/tex]

The current varies wrt time t as :

[tex]q(t) = 4t^3 + 5t + 6[/tex]

(a) At t = 2 seconds, electrical charge is given by :

[tex]q(t) = 4t^3 + 5t + 6\\\\q(2) = 4(2)^3 + 5(2) + 6\\\\q=48\ C[/tex]

(b) Current is given by :

[tex]I=\dfrac{dq}{dt}\\\\I=\dfrac{d(4t^3 + 5t + 6)}{dt}\\\\I=12t^2+5[/tex]

Instantaneous current at t = 1 s is,

[tex]I=12(1)^2+5=17\ A[/tex]

(c) Current is, [tex]I=12t^2+5[/tex]

Current density is given by electric current per unit area.

[tex]J=\dfrac{I}{A}\\\\J=\dfrac{(12t^2+5)}{0.0002}\\\\J=5000(12t^2+5)\ A/m^2[/tex]

Therefore, it is the required explanation.