Answer:
c. between 0.01 and 0.001
Step-by-step explanation:
Given :
n = 40
x = 12
P = 0.5
H0: p = 0.50
Ha :p < 0.50
Sample proportion, p' = [tex] \frac{x}{n} = \frac{12}{40} = 0.3[/tex]
This is a lower tailed test
Standard deviation will be:
[tex] \sigma = \sqrt{\frac{P(1 - P)}{n}} = \sqrt{\frac{0.5(1 - 0.5)}{40}} = 0.0791 [/tex]
For test statistic :
[tex] = \frac{0.3 - 0.5}{0.0791} = -2.529 ≈ -2.53 [/tex]
p-value wil be:
(P < Zobserved) = (P < -2.53)
From the normal distribution table,
NORMSDIST(-2.53) = 0.0057060 ≈ 0.0057
p-value = 0.0057
Therefore the p-value is between
c. between 0.01 and 0.001.