A craftsman can sell 20 jewelry sets for $600 each. He knows that for each additional set he makes, the price of each set will decrease by $10. How many jewelry sets should he make if he wants to maximize his earnings?

Respuesta :

Answer:

40 jewelry sets

Step-by-step explanation:

Step 1: assign variables

x = additional # of sets

total # of sets = 20 + x

price = 600 - 10x

Step 2: make an equation

f(x) = (20 + x)(600 - 10x)

Step 3: find x intercepts

0 = (20 + x)(600 - 10x)

x = -20,  x=60

Step 4: find the midpoint/average of x intercepts

(60 - 20) / 2 = 20

Step 5: plug it into the "total # of sets" equation

20 + 20 = 40

40 jewelry sets!

The number of jewelry sets that should make if he wants to maximize his earnings is 40 jewelries.

Based on the information given, the equation to solve the question will be:

f(x) = (20 + x)(600 - 10x)

Then, we'll find the x-intercept which will be:

0 = (20 + x)(600 - 10x)

x = -20 and 69

The midpoint of the x-intercept will be:

= (60 - 20) / 2

= 40/2

= 20

Since the total number of sets is 20 + x. Then, this'll be:

= 20 + 20 = 40

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