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Distance in scientific notation
Mercury: 57,909,000 57,909 x 10^3
Earth 92,960,000 9,296 x 10^4
Venus: 67,240,000 6,724 x 10^4
Mars: 141,600,000 1,416 x 10^5
Jupiter 483,800,000 4,838 x 10^5
Saturn 888,200,000 8,882 x 10^5
Uranus 1,787,000,000 1,787 x 10^6
Neptune 2,795,000,000 2,795 x 10^6

Required:
a. Convert each of the distances that you have recorded into scientific notation.

b. Answer the following questions using the data you have found. Show your work on all questions as indicated.

A. If a spacecraft was parked on Venus and needed to make a flight to Jupiter, how far wouldit need to travel? Show your work and provide your answer in scientific notation. 483,800,000 – 67,240,000 = 416,560,000 = 41,656 x 10^4

B. Mercury, Venus, and Earth are the three planets closest to the Sun. Would their combined distance from the Sun be greater or less than the distance from the sun to Neptune? Show your work and justify your answer. 57,909,000 + 67,240,000 + 92,960,000 = 218,109,000 483,800,000 – 218,109,000 = 265,691,000 = 265,691 x 10^3

C.If Earth was 10 times farther away from the Sun than it is now, which planet would it be closest to? Compare Earth's new distance to that planet. How far apart would they be in standard notation? How far apart in scientific notation? Show your work.

Respuesta :

xero099

Answer:

(See explanation for further information)

Explanation:

a) The distances of each planet with respect to the Sun is:

Mercury - [tex]57.909 \times 10^{6}\,mi[/tex]

Venus - [tex]67.240\times 10^{6}\,mi[/tex]

Earth - [tex]92.960\times 10^{6}\,mi[/tex]

Mars - [tex]141.600\times 10^{6}\,mi[/tex]

Jupiter - [tex]483.800\times 10^{6}\,mi[/tex]

Saturn - [tex]888.200\times 10^{6}\,mi[/tex]

Uranus - [tex]1,787\times 10^{6}\,mi[/tex]

Neptune - [tex]2,795\times 10^{6}\,mi[/tex]

b) The solutions are presented below:

A. The distance between Venus and Jupiter is:

[tex]\Delta s = 483.800\times 10^{6}\,mi-67.240\times 10^{6}\,mi[/tex]

[tex]\Delta s = 416.560\times 10^{6}\,mi[/tex]

B. The combined distance from the Sun is:

[tex]\Delta s = 57.909\times 10^{6}\,mi + 67.240\times 10^{6}\,mi +92.960\times 10^{6}\,mi[/tex]

[tex]\Delta s = 218.109\times 10^{6}\,mi[/tex]

Which is less than the distance from the Sun to Neptune ([tex]2,795\times 10^{6}\,mi[/tex]).

C. The new distance of Earth is [tex]929.60 \times 10^{6}\,mi[/tex] ([tex]929,600,000\,mi[/tex]). Saturn would be the closest planet to Earth, whose distance:

Scientific notation:

[tex]\Delta s = 929.600\times 10^{6}\,mi-888.200\,\times 10^{6}\,mi[/tex]

[tex]\Delta s = 41.4\times 10^{6}\,mi[/tex]

Standard notation:

[tex]\Delta s = 929,600,000\,mi - 888,200,000\,mi[/tex]

[tex]\Delta s = 41,400.000\,mi[/tex]

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