A sample of nitrogen gas is in a 65.0-L automobile air bag and has a pressure of 745 mm Hg. What is the pressure of this sample of gas at the same temperature if it is placed into a 25.0-L bag?
(a) 1940 mm Hg
(b) 5.15 x 10-4 mm Hg
(c) 745 mm Hg
(d) 287 mm Hg

Respuesta :

Answer: a) 1940 mm Hg

Explanation:

To calculate the new pressure, we use the equation given by Boyle's law. This law states that pressure is directly proportional to the volume of the gas at constant temperature.

The equation given by this law is:

[tex]P_1V_1=P_2V_2[/tex]

where,

[tex]P_1\text{ and }V_1[/tex] are initial pressure and volume.

[tex]P_2\text{ and }V_2[/tex] are final pressure and volume.

We are given:

[tex]P_1=745mmHg\\V_1=65.0L\\P_2=?mmHg\\V_2=25.0L[/tex]

Putting values in above equation, we get:

[tex]745\times 65.0L=P_2\times 25.0L\\\\P_2=1940mmHg[/tex]

Thus new pressure of this sample of gas at the same temperature if it is placed into a 25.0-L bag is 1940 mm Hg

Considering the Boyle's law, the correct answer is option a) the pressure of the sample of gas at the same temperature if it is placed into a 25 L bag is 1940 mmHg.

The gas laws are a set of chemical and physical laws that allow determining the behavior of gases in a closed system. The parameters evaluated in these laws are pressure, volume, temperature and moles.

As the volume increases, the gas particles (atoms or molecules) take longer to reach the walls of the container and therefore collide with them fewer times per unit of time. This means that the pressure will be lower because it represents the frequency of collisions of the gas against the walls. In this way pressure and volume are related, determining Boyle's law, one of the gas laws, which says:

"The volume occupied by a given gaseous mass at constant temperature is inversely proportional to pressure"

Boyle's law is expressed mathematically as:

P×V= k

Studying two different states, an initial state 1 and a final state 2, it is satisfied:

P1×V1= P2×V2

In this case, you know:

  • P1= 745 mmHg
  • V1= 65 L
  • P2= ?
  • V2= 25 L

Replacing in Boyle's law:

745 mmHg× 65 L= P2× 25 L

Solving:

(745 mmHg× 65 L)÷ 25 L= P2

1937 mmHg≅ 1940 mmHg = P2

Finally, the correct answer is option a) the pressure of the sample of gas at the same temperature if it is placed into a 25 L bag is 1940 mmHg.

Learn more about the gas laws:

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