Answer:
The correct answer is 0.26 M
Explanation:
The initial concentration of NaCl solution (Ci) is 5.0 M. The initial volume of the solution (Vi) is 13 mL. The final volume is the addition of 240 mL to 13 mL (Vf= 13 mL + 240 mL= 253 mL).
In order to calculate the final concentration of the solution (Cf) we can use the following expression:
Ci x Vi= Cf x Vf
This mathematical expression is often used to calculate concentrations in dilution procedures. So, we introduce Ci, Vi an Vf in the expression and we calculate Cf:
Cf= (Ci x Vi)/Vf= (5.0 M x 13 mL)/253 mL= 0.257 M ≅ 0.26 M
The concentration of the diluted solution is 0.257 M
From the question given above, the following data were obtained:
Volume of stock solution (V₁) = 13 mL
Molarity of stock solution (M₁) = 5 M
Volume of diluted solution (V₂) = 240 + 13 = 253 mL
5 × 13 = M₂ × 253
65 = M₂ × 253
Divide both side by 253
M₂ = 65 / 253
Therefore, the concentration of the diluted solution is 0.257 M
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