Respuesta :
Answer:
Explanation:
Base on the scenario been described in the question, solver tool has been used in the spreadsheet below to solve a linear programming problem with a minimization objective function and all constraints.
We can locate an attached file below.

The equation indicating the constraint on the Bituminous coal's capacity is 300A + 450B ≥ 170,000.
Data and Calculations:
Field A Field B
Operating costs per day $55,000 $45,000
Lignite coal per day (tons) 250 200
Bituminous coal per day (tons) 300 450
Number of days of operation A B
Expected demand:
Lignite coal = 120,000 tons
Bituminous coal = 170,000 tons
Constraint on the capacity of the Bituminous coal = 300A + 450B ≥ 170,000
Where:
A = the operational days of Field A, which minimizes costs
B = the operational days of Field B, which minimizes costs
Thus, the equation that indicates the constraint on the capacity of the Bituminous coal is 300A + 450B ≥ 170,000.
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