A 12kg ball is given an initial velocity of 20m/s and then is rolled along the floor. A friction force of 5N opposes its motion. For what length of time will it roll before stopping. Thanks in advance!
a=F/m =5/12 =0.42 m/s^2 Since the ball stops, it decelerates at a rate of 0.42 m/s^2 before stopping and it’s final velocity is 0 m/s. t=(u-v)/a =(20-0)/0.42 =48 s
