Kana is practicing her golf swing at the driving range. Her first hit can be described by the displacement
(distance and direction) vector d = (55,5). Her second hit can be described by the displacement vector
d2 = (75, 10).

Respuesta :

Answer:

The distance difference between those swings is 20.6, approximately.

Step-by-step explanation:

To find the difference between the distance of each swing, we need to subtract vectors and find the module of the resulting vector.

[tex]d_{1}=(55,5)[/tex] represents the first swing.

[tex]d_{2}=(75,10)[/tex] represents the second swing.

In the image attached, the difference is shown by vector [tex]w[/tex].

Mathematically, this displacement is defined

[tex]w=d_{2}-d_{1}[/tex]

[tex]w=(75,10)-(55,5)\\w=(75-55,10-5)\\w=(20,5)[/tex]

Now, we find its module

[tex]|w|=\sqrt{20^{2} +5^{2} }=\sqrt{400+25}=\sqrt{425}\\ |w| \approx 20.6[/tex]

Therefore, the distance difference between those swings is 20.6, approximately.

Ver imagen jajumonac

Answer:

20.6 is the difference from the first to second hit

Ver imagen thepennypromise