Answer:
2.01 M
Explanation:
Step 1: Calculate the moles of acetic acid (HC₂H₃O₂)
The molar mass of acetic acid is 60.05 g/mol. We will use this data to calculate the moles corresponding to 36.2 g of acetic acid.
[tex]36.2g \times \frac{1mol}{60.05g} = 0.603mol[/tex]
Step 2: Convert the volume of solution to liters
We will use the relation 1000 mL = 1 L. We assume that the volume of solution is that of water (300 mL)
[tex]300mL \times \frac{1L}{1000mL} = 0.300L[/tex]
Step 3: Calculate the molarity of the solution
The molarity is equal to the moles of solute (acetic acid) divided by the liters of solution
[tex]M = \frac{0.603mol}{0.300L} = 2.01 M[/tex]
