Answer:
[tex](1, -3)[/tex]
[tex]y= -3[/tex]
[tex]x= 1[/tex]
Step-by-step explanation:
[tex]6x - 9 = y \\ y = - 3x \\ solve \: using \: comparison \: method[/tex]
[tex]6x-9= -3x \\subtract \:6x\: from \:both sides[/tex]
[tex]-9x= -9\\ divide\: both \:sides\: by \:-9[/tex]
[tex]x= 1\\substitute \:the\: value \:of\: x \:into\: an \:equation[/tex]
[tex]y= -3×1\\ multiply\: -3\: to\: 1[/tex]
[tex]y= -3[/tex]
[tex](1,-3)[/tex]
The solution to the system of linear equation by substitution method is as follows : x = 1 and y = -3
6x − 9 = y
y = −3x
let's substitute the value of y in the first equation as follows;
6x - 9 = -3x
add -3x to both sides of the equation
6x + 3x - 9 = -3x + 3x
9x - 9 = 0
add 9 to both sides of the equation
9x - 9 + 9 = 0 + 9
9x = 9
divide both sides by 9
x = 9 / 9
x = 1
let's find y by substituting the value of x in the second equation
y = -3x
y = -3(1)
y = -3
Therefore, x = 1 and y = -3
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