Answer: Answers below
Step-by-step explanation:
[tex]2y+4x=8[/tex]
Solve for y.
[tex]2y+4x-4x=8-4x\\2y=8-4x\\y=\frac{8-4x}{2}[/tex]
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When x = -2; y = 8
[tex]y=\frac{8-4(-2)}{2}\\y=\frac{8+8}{2}\\ y=\frac{16}{2}\\ y=8[/tex]
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When x = 1 ; y = 2
[tex]y=\frac{8-4(1)}{2}\\y=\frac{8-4}{2}\\ y=\frac{4}{2}\\ y=2[/tex]
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When x = 3 ; y = -2
[tex]y=\frac{8-4(3)}{2}\\y=\frac{8-12}{2}\\ y=\frac{-4}{2}\\ y=-2[/tex]