Answer:
Lateral surface area of the pyramid= [tex]48\,\,inch^2[/tex]
Step-by-step explanation:
The lateral surface area of the pyramid is the area of the all of its four triangular faces, excluding base :
Area of a triangle is:
[tex]=\dfrac{1}{2} \times Base \times Height\\[/tex]
Base= 3 inches
Height=8 inches
Lateral surface area of the pyramid:
[tex]=4(\dfrac{1}{2}\times Base \times Height )\\\\=4(\dfrac{1}{2} \times 3 \times 8 )\\\\=4(\dfrac{1}{2} \times 24 )\\\\=4 \times 12\\\\=48\,\,inch^2[/tex]
Lateral surface area of the pyramid= [tex]48\,\,inch^2[/tex]
