Oil is leaking from an oil tanker, and an expanding circle of oil is spreading on the ocean. The radius. r. of the circle measured in inches is modeled by the function
r(s)=3 sqrt. S, where s is time in seconds.
The area of the spill when s=5 seconds is ___
Pi square inches.

Respuesta :

Answer:

The area of the circle when s = 5 is 45π in²

Step-by-step explanation:

Given

r(s) = 3√s

Required

Area of he circle when s = 5

Provided that the oil spillage from the tanker forms a circle on the surface of the ocean, the area of the spill is calculated by the area of the circle.

Area = πr²

First, the value of r must be calculated

r = 3√s

When s = 5

r = 3√5 in

Substitute 3√5 for r in the equation of a circle.

A = πr² becomes

A = π(3√5)²

Open the bracket.

A = π * 3√5 * 3√5

A = π * 9 * 5

A = 45π

Hence, the area of the circle when s = 5 is 45π in²

The area of the oil spill is 2.924π square inches.

Since the radius of the circle of oil spread is modelled by the function r = ∛s where s = time in seconds.

The area of the oil spill A = πr²

= π(∛s)²

So, we need to find the area of the oil spill when s = 5.

So, A = π(∛s)²

A = π(∛5)²

A = π(1.7099)²

A = 2.924π square inches.

So, the area of the oil spill is 2.924π square inches.

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