Respuesta :
Answer:
The area of the circle when s = 5 is 45π in²
Step-by-step explanation:
Given
r(s) = 3√s
Required
Area of he circle when s = 5
Provided that the oil spillage from the tanker forms a circle on the surface of the ocean, the area of the spill is calculated by the area of the circle.
Area = πr²
First, the value of r must be calculated
r = 3√s
When s = 5
r = 3√5 in
Substitute 3√5 for r in the equation of a circle.
A = πr² becomes
A = π(3√5)²
Open the bracket.
A = π * 3√5 * 3√5
A = π * 9 * 5
A = 45π
Hence, the area of the circle when s = 5 is 45π in²
The area of the oil spill is 2.924π square inches.
Since the radius of the circle of oil spread is modelled by the function r = ∛s where s = time in seconds.
The area of the oil spill A = πr²
= π(∛s)²
So, we need to find the area of the oil spill when s = 5.
So, A = π(∛s)²
A = π(∛5)²
A = π(1.7099)²
A = 2.924π square inches.
So, the area of the oil spill is 2.924π square inches.
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