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Given: △RST and Side RS = 14 in., Side ST = 10 in., Side TR = 16 in. List the interior angles of △RST in order from smallest to largest. label the side lengths) *

Respuesta :

Answer:

∠R < ∠T < ∠S

Step-by-step explanation:

In a triangle, the larger the side, the larger the angle that is opposite to that side. We can first order the sides from shortest to longest and then convert them into their corresponding angles.

10 < 14 < 16

ST < RS < TR

From there we can then replace the sides with their corresponding angles, the angle labels each are named as the one letter that is not included in the name.

∠R < ∠T < ∠S

Therefore this is the order of interior angles of the triangle from smallest to largest.

In the given triangle, ∠R < ∠T < ∠S. Angle R is the smallest angle and angle S is the largest angle.

What is a triangle?

'A triangle is a three-sided polygon, which has three vertices. The three sides are connected with each other end to end at a point, which forms the angles of the triangle. The sum of all three angles of the triangle is equal to 180 degrees.'

According to the given problem,

In a triangle, from the properties of triangles, the angle opposite to the largest side is the largest angle and the angle opposite to the smallest side is the smallest angle.

Arranging the sides from smallest to largest,

RS = 14 inches

ST = 10 inches

TR = 16 inches

10 inches < 14 inches < 16 inches

ST < RS < TR

Now, arranging the angles in accordance to their opposite sides,

∠R < ∠T < ∠S

Hence, we can conclude, the angles of the triangle from smallest to largest is ∠R < ∠T < ∠S.

Learn more about triangles here: https://brainly.com/question/2773823

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