Respuesta :
Answer:
The answer is "[tex]SO_3 = 1.85 \times 10^{24} \ \ molecules[/tex]".
Explanation:
In the given question some information is missing, that chemical reaction, which can be described as follows:
[tex]SO_3+H_2O= H_2SO_4[/tex]
where,
[tex]SO_3 =[/tex] Sulfur trioxide
[tex]H_2O =[/tex] water
[tex]H_2SO_4[/tex]= Sulfuric acid
calculating molecules of sulfur trioxide:
Formula:
[tex]PV =nRT \\[/tex]
Where,
[tex]P= 1 \\\ T= 273.15 K\\R= 0.08206 \ \ \frac{l}{mol} \\V = 68.9 l\\n= ?\\\\n =\frac{PV}{RT} \\\\O_2= \frac{1 \times 68.9}{0.08206 \times 273.15} \\\\O_2 = 3.7 mole\\\\\ if \ mole \ ratio \ is \ 1: 1 \ where SO_3 : H_2O \\\\\therefore SO_3 = 3.07 mole \\\\1 \ mole \ of \ any \ subtance = 6. 022 \times 10^{23} molecule \\\\\ for \ n \ molecule = 6. 022 \times 10^{23} \times 3.07 \\\\ SO_3 = 1.85 \times 10^{24} molecules[/tex]
