Answer:
h = $47.40, j = $63.15, r = $15.80
Step-by-step explanation:
This a systems of equation problem:
j + h + r = 126.35 (how much the boys raised together)
j = 15.75 + h (if Horacio had 15.75 more, then the boys would be equal)
h = 3r (if Rashad tripled his money, then he and Horacio would by equal)
You need to use substitution to find how much one boy made, then plug it into the other equations. Let's solver for Horacio first.
(15.75 + h) + h + (h/3) = 126.35
7h/3 = 110.6, 7h = 331.8
h = $47.40
j = 15.75 + 47.40, j = $63.15
47.40 = 3r, r = $15.80
Double check by adding of the prices together:
$47.40 + $63.15 + $15.80 = $126.35
Answer:
Step-by-step explanation:
Let the money raised by Horacio be x
The money raised by Rashad = (1/3)*x
The money raised by Jack = x + 15.75
Total money raised by three friends = $ 126.35
[tex]x+\frac{1}{3}x+x+15.75=126.35\\\\2x+\frac{1}{3}x+15.75=126.35\\\\\frac{7}{3}x+15.75=126.35\\\\\frac{7}{3}x=126.35-15.75\\\\\frac{7}{3}x=110.60\\\\x=110.60*\frac{3}{7}\\\\x=15.80*3[/tex]
x = $ 47.40
The money raised by Horacio =$47.40
The money raised by Jack = 47.40 + 15.75 = $63 .15
The money raised by Rashad = 47.40/3 = $ 15.80
