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+ = qu(sine)
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A straight wire segment in a circuit is 30.0 m long and moves at 2.0 m/s perpendicular to
a magnetic field. A 6.0-V EMF is induced. What is the magnetic field?
0
0.10 N
O 1.00
O
0.10 T
O
1.01​

Respuesta :

temdan2001

Answer: B = 0.1 Tesla

Explanation: Given that the

Emf = 6.0 V

Length L = 30 m

Speed V = 2 m/s

B = ?

The induced EMF = BVL

6 = 30 × 2 × B

B = 6/60

B = 0.1 Tesla

The magnetic field B = 0.1 Tesla.

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