Answer:
Explanation:
This is a momentum / impulse question. Δp = F•(Δt)
The momentum of the car goes from 1150*85 = 97750 to 0 in 0.1 seconds.
From this we get the equation 97750 = F(.1)
a) F = 977500 N
For part b), the change in momentum is unchanged, so we must increase the time in order to decrease the force.
97750 = 200000(t)
b) t = 0.49 s or .5 s considering sig figs which means an increase factor of 5
This is a momentum/impulse question. Δp = F•(Δt)
The momentum of the car goes from 1150*85 = 97750 to 0 in 0.1 seconds.
From this, we get the equation 97750 = F(.1)
a) F = 977500 N
For part b), the change in momentum is unchanged, so we must increase the time in order to decrease the force.
97750 = 200000(t)
b) t = 0.49 s or .5 s considering sig figs which means an increase factor of 5.
The forward force is the force of the road pushing forward on the car due to friction between the wheels and the road surface. That's the description. As for the name and label, we tend to call it an applied force since it is the force applied by the road on the car.
A car moving at a constant speed (uniform motion) has all forces acting on it balanced. In this case, the two backward forces (air resistance and friction) perfectly balance the applied force of the wheels on the road in the opposite direction.
Learn more about What is the applied force on a car? here: https://brainly.com/question/8119756
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