Answer:
[tex] s_A = 5.21[/tex]
[tex] s_B =4.88[/tex]
[tex] s_C = 6.06[/tex]
[tex]s_D =3.39[/tex]
We need to remember that the deviation is a measure od disperion and for this case is the deviation is larger then we have more spread out the distribution of interest. And largest deviation for this case is from the dataset C so then the answer would be:
D. Data set C
Step-by-step explanation:
For this case the standard deviation can be calculated with the following formula:
[tex] s = \sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}[/tex]
And for this case we have the deviations for each dataset are given by:
[tex] s_A = 5.21[/tex]
[tex] s_B =4.88[/tex]
[tex] s_C = 6.06[/tex]
[tex]s_D =3.39[/tex]
We need to remember that the deviation is a measure od disperion and for this case is the deviation is larger then we have more spread out the distribution of interest. And largest deviation for this case is from the dataset C so then the answer would be:
D. Data set C