the bow has a base area of 9/10 square foot and a height of 1/3 foot.How much packing material is required to fill the box

Respuesta :

Answer:

The amount of material to fill the box is: 0.3 [tex]ft^3[/tex]

Step-by-step explanation:

Recall that the volume (V) of a box is the product of the area of its base (B) times its height (H):  V = B * H

Therefore, since in this case the area of the base is:

[tex]B=\frac{9}{10} \,ft^2[/tex]

and the box's height is:

[tex]H=\frac{1}{3} \,ft[/tex]

The total volume of the box (and what you need of material to fill it) is:

[tex]V=B*H\\V=\frac{9}{10} \,\,ft^2*\frac{1}{3} \,ft\\V=\frac{9*1}{10*3} \,ft^3\\V=\frac{3}{10} \,ft^3\\V= 0.3\,\,t^3[/tex]