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ABCD is a parallelogram. EDC is a straight line. F is the point on AD so that BFE is a straight line. Angle EFD = 35q Angle DCB = 75q Show that angle ABF = 70q Give a reason for each stage of your working.

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Answer:

Step-by-step explanation:

Angle DFE = AFB = 35° ( Opposite angles)

Angle ECB = BAF = 75° (Opposite angles of parallelogram )

in ∆AFB

Two angles are 35° and 75° . Since Sum of angles be 180° . So third angle

ABF = 180°- (75°+35°) = 70°

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