Answer:
The force constant of the spring is 735 N/m.
Explanation:
It is given that,
Mass of fruit, m = 1500 g = 1.5 kg
Compression in the scale, x = 0.02 m
We need to find the force constant of the spring on the scale. The force acting on the scale is given by using Hooke's law. So,
[tex]F=-kx[/tex]
Also, F = mg
[tex]mg=kx[/tex]
k is force constant
[tex]k=\dfrac{mg}{x}\\\\k=\dfrac{1.5\times 9.8}{0.02}\\\\k=735\ N/m[/tex]
So, the force constant of the spring is 735 N/m.
