Answer:
M = 0.177
Explanation:
First, we have to find the molar mass of potassium iodine (KI).
K = 39.098
I = 126.904
Now, add these values together to get the molar mass of KI
39.098 + 126.904 = 166.0028
Now, it's time to do a grams to moles conversion.
35.0 g KI * [tex]\frac{1 mol KI}{166.0028 g KI}[/tex] = [tex]\frac{35.0}{166.0028}[/tex] = 0.212 mol KI
Now, we can find the molarity of this solution.
Molarity (M) = [tex]\frac{mol}{L}[/tex]
M = [tex]\frac{0.212 mol KI}{1.200 L}[/tex] = 0.177 M
The molarity (M) of this solution is 0.177.
