Respuesta :
Answer:
22.6 g NaBr
Explanation:
(41.3g AgBr) / (187.7722g AgBr/mol) x (1 mol NaBr / 1 mol AgBr) x (102.8938g NaBr/mol) = 22.6 g NaBr
Answer:
22.6 g NaBr
Explanation:
(41.3g AgBr) / (187.7722g AgBr/mol) x (1 mol NaBr / 1 mol AgBr) x (102.8938g NaBr/mol) = 22.6 g NaBr