A weather balloon full of helium with a volume of 12.9 L at 22°C is sitting
inside an aircraft hangar. The temperature of the hangar decreases to 13°C.
Which equation would be easiest to use to find the new volume of the
balloon?
A. P=F/A
B. P1V1=P2V2
C.(V1/T1)=(V2/T2)
D. PV=nRT

Respuesta :

Answer: The equation would be easiest to use to find the new volume of the balloon is [tex]\frac{V_1}{T_1}=\frac{V_2}{T_2}[/tex]

Explanation:

To calculate the final temperature of the system, we use the equation given by Charles' Law. This law states that volume of the gas is directly proportional to the temperature of the gas at constant pressure.

Mathematically,

[tex]\frac{V_1}{T_1}=\frac{V_2}{T_2}[/tex]

where,

[tex]V_1\text{ and }T_1[/tex] are the initial volume and temperature of the gas.

[tex]V_2\text{ and }T_2[/tex] are the final volume and temperature of the gas.

We are given:

[tex]V_1=12.9L\\T_1=22^oC=(22+273)K=295K\\V_2=?\\T_2=13^oC=(13+273)K=286K[/tex]

Putting values in above equation, we get:

[tex]\frac{12.9}{295}=\frac{V_2}{286}[/tex]

The equation would be easiest to use to find the new volume of the

balloon is [tex]\frac{V_1}{T_1}=\frac{V_2}{T_2}[/tex]

Answer :C.(V1/T1)=(V2/T2)

Explanation:APÉX