Alan used the expression StartFraction 5 over 9 EndFraction (F minus 32), where F is a temperature in degrees Fahrenheit, to convert a temperature from Fahrenheit to Celsius. He evaluated the expression as shown below and found that 45 degrees Fahrenheit was equivalent to –7 degrees Celsius.

StartFraction 5 over 9 EndFraction (F minus 32) = StartFraction 5 over 9 (45 minus 32) = 25 minus 32 = negative 7

What error did Alan make?

He substituted 45 for F instead of –7 and should have found the answer to be Negative 21 and two-thirds degrees Celsius.

He did not combine within the parentheses first before multiplying and should have found the answer to be 7 and StartFraction 2 over 9 EndFraction degrees Celsius.

He multiplied 45 by the fraction incorrectly and should have found the answer to be 49 degrees Celsius.

He divided 5F by 9 before subtracting 32 and should have found the answer to be 21 and StartFraction 4 over 9 EndFraction degrees Celsius.

Question

10-05-2020
Mathematics

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Alan used the expression StartFraction 5 over 9 EndFraction (F minus 32), where F is a temperature in degrees Fahrenheit, to convert a temperature from Fahrenheit to Celsius. He evaluated the expression as shown below and found that 45 degrees Fahrenheit was equivalent to –7 degrees Celsius.

StartFraction 5 over 9 EndFraction (F minus 32) = StartFraction 5 over 9 (45 minus 32) = 25 minus 32 = negative 7

What error did Alan make?

He substituted 45 for F instead of –7 and should have found the answer to be Negative 21 and two-thirds degrees Celsius.

He did not combine within the parentheses first before multiplying and should have found the answer to be 7 and StartFraction 2 over 9 EndFraction degrees Celsius.

He multiplied 45 by the fraction incorrectly and should have found the answer to be 49 degrees Celsius.

He divided 5F by 9 before subtracting 32 and should have found the answer to be 21 and StartFraction 4 over 9 EndFraction degrees Celsius.

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itmye84 itmye84 · Answer 1 · 2020-05-10T02:10:44+02:00

[tex]C=\frac{5}{9} (F-32)[/tex] [C = Celsius F = Fahrenheit]

Alan found 45°F = -7°C, his work:

[tex]C=\frac{5}{9} (F-32)=\frac{5}{9} (45-32)=25-32=-7[/tex]

So he distributed 5/9 into (45 - 32), but he only distributed it to 45. It would've been:

[tex]C=\frac{5}{9} (45-32)=(\frac{5}{9} )45+(\frac{5}{9} )(-32)=25-\frac{160}{9} =\frac{65}{9}[/tex]

What error did Alan make?

#1: He substituted 45 for F instead of –7 and should have found the answer to be Negative 21 and two-thirds degrees Celsius.

This is wrong because he used 45 degrees Fahrenheit, not -7 degrees Fahrenheit.

#2: He did not combine within the parentheses first before multiplying and should have found the answer to be 7 and StartFraction 2 over 9 EndFraction degrees Celsius.

This is right because he should've combined inside the parentheses first before multiplying the fraction.

[tex]C=\frac{5}{9} (45-32)=\frac{5}{9} (13)=\frac{65}{9} =7\frac{2}{9}[/tex]

#3: He multiplied 45 by the fraction incorrectly and should have found the answer to be 49 degrees Celsius.

This is wrong because 45 multiplied by the fraction does = 25

#4: He divided 5F by 9 before subtracting 32 and should have found the answer to be 21 and StartFraction 4 over 9 EndFraction degrees Celsius.

This is wrong because he didn't do this

hudsonoflife hudsonoflife · Answer 2 · 2020-10-16T22:34:58+02:00

hudsonoflife hudsonoflife

16-10-2020

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