Answer:
Explanation:
mole of O₂ = [tex]\frac{8}{32}[/tex]
= .25 moles
mole of CO₂
= [tex]\frac{8}{44}[/tex]
= .1818 moles
moles of SO₂
[tex]\frac{8}{64}[/tex]
= .125 moles
Total moles of gas
= .5568 moles.
total volume of gas mixture
= 22.4 x .5568 liter ( volume of one mole of any gas = 22.4 liter)
= 12.47 liter.
gas will exert partial pressure according to their mole fraction
gas having greatest no of moles in the total mole will have greatest mole fraction so
O₂ will have greatest partial pressure.
