Respuesta :

mathstudent55

Answer:

Problem B: x = 12; m<EFG = 48

Problem C: m<G = 60; m<J = 120

Step-by-step explanation:

Problem B.

Angles EFG and IFH are vertical angles, so they are congruent.

m<EFG = m<IFH

4x = 48

x = 12

m<EFG = m<IFH = 48

Problem C.

One angle is marked a right angle, so its measure is 90 deg.

The next angle counterclockwise is marked 30 deg.

Add these two measures together, and you get 120 deg.

<J is vertical with the angle whose measure is 120 deg, so m<J = 120 deg.

Angles G and J from a linear pair, so they are supplementary, and the sum of their measures is 180 deg.

m<G = 180 - 120 = 60

xew

The drag slides I can't do in brainly that well, but I can do the first slides A B C D

A:

4x + 23 = 55

4x = 32

x = 8

angle DBC = 32

B:

4x = 48 (bcuz verticle angles)

angle EFG = 48

x = 12

C:

angle G = 180 - 90 - 30 = 60

angle J = 180 - 60 = 120

D:

4x + x + 11 = 131

5x = 120

x = 24

angle JMK = (24 x 4) = 96