what is the value of x? show all the work

Answer:
9 cm
Step-by-step explanation:
You can use the pythagorean theorem to find x here. Since [tex]AB^2 + BC^2=AC^2, AC^2-BC^2=AB^2[/tex]. [tex]\sqrt{\sqrt{117}^2-6^2}=\sqrt{117-36}=\sqrt{81}=9[/tex]. Hope this helps!
Answer:
9 cm
Step-by-step explanation:
Using pythagoras theorem
(Sqrt(117))² = 6² + x²
117 = 36 + x²
x² = 81
x = 9