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A cone-shape mountain of garden soil is dumped on a flat surface. If the diameter of the
mountain is 12 cm and its volume is 4800 cm cubed. how high is the mountain?

Respuesta :

Hrishii

Answer:

127.4 cm

Step-by-step explanation:

Diameter = 12 cm

Therefore, radius r = 12/2 = 6 cm

[tex]V_{soil} = \frac{1}{3} \pi {r}^{2}h \\ 4800 = \frac{1}{3} \times 3.14 \times {6}^{2} \times h \\ 4800 = \frac{1}{3} \times 3.14 \times 36 \times h \\ 4800 = 3.14 \times 12 \times h \\ h = \frac{4800}{3.14 \times 12} \\ h = \frac{400}{3.14} \\ h = 127.388535 \\ h = 127.4 \: cm \\ [/tex]

Hence,height of mountain is 127.4 cm

PunIntended

Answer:

127.3 centimetres

Step-by-step explanation:

The volume of a cone is denoted by: [tex]V=\frac{1}{3} \pi r^2h[/tex], where r is the radius and h is the height.

Here, the diameter is 12, but remember that diameter is simply twice the radius. That means the radius is r = 12/2 = 6 cm.

We know the volume is V = 4800, so plug in these values to find h:

4800 = (1/3) * π * 6² * h

h ≈ 127.3 centimetres