Use the method of symmetry to find the extreme value of each quadratic function and the value of x for which it occurs h(x)=1/2(3-x)(2-x)

Respuesta :

Answer:

x=2, and x=3

Step-by-step explanation:

0=1/2*(3-x)(2-x)

x=2, and x=3

The axis of symmetry of a parabola is a vertical line that divides the parabola into two congruent halves.

Given quadratic equation have minimum value of  -1/8  at x=5/2 .

If a quadratic equation have standard form of [tex]y = ax^2 + bx + c[/tex], where a, b, and c equal all real numbers. We can use the formula [tex]x = -b / 2a[/tex] to find the line of symmetry.

[tex]h(x)=1/2(3-x)(2-x)\\\\h(x)=\frac{1}{2} x^2-\frac{5}{2}x+3[/tex]

Here,  a=1/2 , b= -5/2 and c=3

So, line of symmetry  [tex]x=\frac{-(-5/2)}{2(1/2)} =5/2[/tex]

[tex]h(5/2)=1/2(3-5/2)(2-5/2)\\\\=1/2*(1/2)(-1/2)\\=-1/8[/tex]

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