Respuesta :
Answer:
the answer is in the explanation
Step-by-step explanation:
we are given
sample size [tex]n_{1} = n_{2}[/tex] = 10 for each formulation
mean [tex]\bar{x} _{1}[/tex] (formulation 1) = 121
mean [tex]\bar{x} _{2}[/tex] (formulation 2) = 112
s (standard deviation ) = 8 mins for each case
null hypothesis [tex]H_{0}[/tex] μ2 = μ1 (both have average same time)
alternative hypothesis [tex]H_{1}[/tex] μ2 < μ1
under [tex]H_{0}[/tex] the test statistics is
[tex]t = \frac{\bar{x}_{2} - \bar{x}_{1} }{s\sqrt{\frac{1}{n_{1} }+ \frac{1}{n_{1}} } }[/tex]
[tex]t = \frac{112 - 121 }{8\sqrt{\frac{1}{10 }+ \frac{1}{10} } }[/tex]
t = -2.5
ItI = 2.5
The P-value at ItI = 2.5 at [tex]\alpha[/tex] = 0.05 μ = 0.010699
check the remaining solution and diagram in the attached image
