Answer:
A) 0.303
The probability that a randomly selected student from the class has brown eyes , given they are male
[tex]P(\frac{B}{M} ) = 0.3030[/tex]
Step-by-step explanation:
Explanation:-
Given data
Brown Blue Hazel Green
Females 13 4 6 9
Males 10 2 9 12
Let 'B' be the event of brown eyes
Total number of males n(M) = 33
Let B/M be the event of randomly selected student from the class has brown eyes given they are male
The probability that a randomly selected student from the class has brown eyes , given they are male
[tex]P(\frac{B}{M} ) = \frac{n(B)}{n(M)}[/tex]
From table the brown eyes from males = 10
[tex]P(\frac{B}{M} ) = \frac{10}{33}[/tex]
[tex]P(\frac{B}{M} ) = 0.3030[/tex]
Final answer:-
The probability that a randomly selected student from the class has brown eyes , given they are male
[tex]P(\frac{B}{M} ) = 0.3030[/tex]
