Answer:
[tex]\Delta T=194^oC[/tex]
Explanation:
Hello,
In this case, in terms of the heat, mass, heat capacity and change in temperature, we can analyze thermal changes as:
[tex]Q=mCp\Delta T\\[/tex]
In such a way, we compute the required change in temperature as shown below:
[tex]\Delta T=\frac{Q}{mCp}=\frac{480.0cal}{75.0g*0.033\frac{cal}{g^oC} } \\\\\Delta T=194^oC[/tex]
Such change in temperature is positive indicating an increase in the temperature as the involved heat is positive, in means that heat was added to increase the temperature.
Best regards.
